How to calculate atan2 in cleo script for gta sa android?

[Gdzin]

Como calcular atan2 no script cleo para gta sa android?

 

[Kross]

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[Kross]

gdzin question: How to calculate atan2 in cleo script for gta sa android?

 

[Parazitas]

atan2(y,x) snippet

Computes the arctangent angle in the Euclidean plane, given in radians. atan2 is far more superior because atan can only return an angle of -90 to +90 degrees or -pi/2 to pi/2. atan2 is mostly used on "Aimbots". I always use atan2 beside of atan when I am dealing with geometric computaions...

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[Gdzin]

the method calling the atan2 function from memory is not possible because there is no direct function that calculates atan2 in the arm architecture, only in the x86 architecture which is fpatan, and the other method is not possible either because there is no opcode 0C08: math 31@ = arctangent 30@ // (float)

 

[Gdzin]

0086: $Point_X = $Enemy_X
0086: $Point_Y = $Enemy_Y
0061: $Point_X -= $Camera_X
0061: $Point_Y -= $Camera_Y
0061: $Enemy_Z -= $Camera_Z
0604: get_Z_angle_for_point $Point_X $Point_Y store_to $Angle_Z
$Angle_Z -= 90.0
$Angle_Z /= 57.29578
0509: $Distance = distance_between_XY $Camera_X $Camera_Y and_XY $Enemy_X $Enemy_Y
// $Angle_X = atan2($Distance, $Enemy_Z);
0A25: set_camera_on_players_X_angle $Angle_X Z_angle $Angle_Z


is there any other way to make this aimbot work?

 

[Parazitas]

0086: $Point_X = $Enemy_X
0086: $Point_Y = $Enemy_Y
0061: $Point_X -= $Camera_X
0061: $Point_Y -= $Camera_Y
0061: $Enemy_Z -= $Camera_Z
0604: get_Z_angle_for_point $Point_X $Point_Y store_to $Angle_Z
$Angle_Z -= 90.0
$Angle_Z /= 57.29578
0509: $Distance = distance_between_XY $Camera_X $Camera_Y and_XY $Enemy_X $Enemy_Y
// $Angle_X = atan2($Distance, $Enemy_Z);
0A25: set_camera_on_players_X_angle $Angle_X Z_angle $Angle_Z


is there any other way to make this aimbot work?

Just make your own function of arctangent...
Use Google to find out how it works and start making calculations...

 

[Parazitas]

Example:

def arctan(x, terms):
    result = 0
    sign = 1

    for n in range(1, 2*terms, 2):
        term = sign * (x ** n) / n
        result += term
        sign *= -1

    return result

x = 0.5 # Value for which you want to calculate arctan
terms = 10 # Number of terms in the series

approx_arctan = arctan(x, terms)
print(approx_arctan)

This code snippet calculates an approximation of the arctangent of 0.5 using the Taylor series expansion with 10 terms. You can adjust the x value and the number of terms (terms) to see how the approximation changes.

Remember that while this approach works for small values of x, it may not be the most efficient or accurate method for larger values.

 

[Parazitas]

C++ example

#include <iostream>
#include <cmath>

double arctan(double x, int terms) {
    double result = 0.0;
    double sign = 1.0;

    for (int n = 1; n <= 2 * terms; n += 2) {
        double term = sign * (std::pow(x, n) / n);
        result += term;
        sign *= -1.0;
    }

    return result;
}

int main() {
    double x = 0.5; // Value for which you want to calculate arctan
    int terms = 10; // Number of terms in the series

    double approx_arctan = arctan(x, terms);
    std::cout << "Approximate arctan(" << x << ") = " << approx_arctan << std::endl;

    return 0;
}